100x^2-120+36=25

Solution for 100x^2-120+36=25 equation:

100x^2-120+36=25

We move all terms to the left:

100x^2-120+36-(25)=0

We add all the numbers together, and all the variables

100x^2-109=0

a = 100; b = 0; c = -109;
Δ = b2-4ac
Δ = 02-4·100·(-109)
Δ = 43600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43600}=\sqrt{400*109}=\sqrt{400}*\sqrt{109}=20\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{109}}{2*100}=\frac{0-20\sqrt{109}}{200}
=-\frac{20\sqrt{109}}{200}
=-\frac{\sqrt{109}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{109}}{2*100}=\frac{0+20\sqrt{109}}{200}
=\frac{20\sqrt{109}}{200}
=\frac{\sqrt{109}}{10}
$